m^2=73

Solution for m^2=73 equation:

m^2=73

We move all terms to the left:

m^2-(73)=0

a = 1; b = 0; c = -73;
Δ = b2-4ac
Δ = 02-4·1·(-73)
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{73}}{2*1}=\frac{0-2\sqrt{73}}{2}
=-\frac{2\sqrt{73}}{2}
=-\sqrt{73}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{73}}{2*1}=\frac{0+2\sqrt{73}}{2}
=\frac{2\sqrt{73}}{2}
=\sqrt{73}
$